2y(5y^3+3)(5y^3-3)=

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Solution for 2y(5y^3+3)(5y^3-3)= equation:


Simplifying
2y(5y3 + 3)(5y3 + -3) = 0

Reorder the terms:
2y(3 + 5y3)(5y3 + -3) = 0

Reorder the terms:
2y(3 + 5y3)(-3 + 5y3) = 0

Multiply (3 + 5y3) * (-3 + 5y3)
2y(3(-3 + 5y3) + 5y3 * (-3 + 5y3)) = 0
2y((-3 * 3 + 5y3 * 3) + 5y3 * (-3 + 5y3)) = 0
2y((-9 + 15y3) + 5y3 * (-3 + 5y3)) = 0
2y(-9 + 15y3 + (-3 * 5y3 + 5y3 * 5y3)) = 0
2y(-9 + 15y3 + (-15y3 + 25y6)) = 0

Combine like terms: 15y3 + -15y3 = 0
2y(-9 + 0 + 25y6) = 0
2y(-9 + 25y6) = 0
(-9 * 2y + 25y6 * 2y) = 0
(-18y + 50y7) = 0

Solving
-18y + 50y7 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '2y'.
2y(-9 + 25y6) = 0

Factor a difference between two squares.
2y((3 + 5y3)(-3 + 5y3)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'y' equal to zero and attempt to solve: Simplifying y = 0 Solving y = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y = 0

Subproblem 2

Set the factor '(3 + 5y3)' equal to zero and attempt to solve: Simplifying 3 + 5y3 = 0 Solving 3 + 5y3 = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 5y3 = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 5y3 = 0 + -3 5y3 = 0 + -3 Combine like terms: 0 + -3 = -3 5y3 = -3 Divide each side by '5'. y3 = -0.6 Simplifying y3 = -0.6 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 3

Set the factor '(-3 + 5y3)' equal to zero and attempt to solve: Simplifying -3 + 5y3 = 0 Solving -3 + 5y3 = 0 Move all terms containing y to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + 5y3 = 0 + 3 Combine like terms: -3 + 3 = 0 0 + 5y3 = 0 + 3 5y3 = 0 + 3 Combine like terms: 0 + 3 = 3 5y3 = 3 Divide each side by '5'. y3 = 0.6 Simplifying y3 = 0.6 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Solution

y = {0}

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